Postgres convert string to number8/25/2023 Try this: SELECT FROM table WHERE myint mytext::int8 The :: cast operator is historical but convenient. ![]() If other exceptions are even remotely common, it pays to filter invalid strings without raising an exception. postgres convert number to string Comment 1 xxxxxxxxxx Because the number can be up to 15 digits, you'll need to cast to an 64 bit (8-byte) integer. If empty strings are common it makes sense to catch that separately. postgres convert number to string Comment 1 xxxxxxxxxx Because the number can be up to 15 digits, youll need to cast to an 64 bit (8-byte) integer. Regular expressions are also expensive - even if on a much smaller scale. The function can easily be adapted for any data type conversion.Įntering an exception block is expensive. Note that the simple regular expression does not catch all violations (like "out of range"). Find not-integer values in a string column.This returns 0 for an empty string or any other invalid input. RETURN 0 - or null ? - other invalid input, like "out of range" IF $1 = '' THEN - special case for empty string IF that is commonĮLSIF $1 !~ '^*\d+$' THEN - obviously invalid (would also catch '') Also, the question asks to convert empty strings ( '') to 0, but not other "invalid input syntax" or "out of range" input: CREATE OR REPLACE FUNCTION convert_to_int(text) It works similar to the simpler solutions, except will give 0 when the value to convert is non-digit characters only, such as "bad": db=> select CAST((COALESCE(NULLIF(REGEXP_REPLACE('no longer bad!', '+', '', 'g'), ''), '0')) AS INTEGER) To address Chris Cogdon's concern with the solution not giving 0 for all cases, including a case such as "bad" (no digit characters at all), I made this adjusted statement: CAST((COALESCE(NULLIF(REGEXP_REPLACE(myfield, '+', '', 'g'), ''), '0')) AS INTEGER) The most efficient way is to have the collation itself handle this internally. Sorting a '2' stored in a string type before the '15' can be done in a few ways. Then text/varchar values like "b3ad5" will also give numbers db=> select CAST(REGEXP_REPLACE(COALESCE('b3ad5','0'), '+', '', 'g') AS INTEGER) 27 Sorting strings naturally puts '15' before '2' because the first digit in the '15' is a '1', which sorts before '2'. CAST(REGEXP_REPLACE(COALESCE(myfield,'0'), '+', '', 'g') AS INTEGER) If you need to handle the possibility of the field having non-numeric text (such as "100bad") you can use regexp_replace to strip non-numeric characters before the cast. How can I convert it into a decimal/float from a string containing a as shown above Tried, score::decimal but it complains as, ERROR: invalid input syntax for type numeric: '95.00' SQL state: 22P02 cast also does not seem to work. ![]() Some test cases to demonstrate: db=> select CAST((COALESCE(NULL,'0')) AS INTEGER) ĭb=> select CAST((COALESCE('','0')) AS INTEGER) ĭb=> select CAST((COALESCE('4','0')) AS INTEGER) ĭb=> select CAST((COALESCE('bad','0')) AS INTEGER) ĮRROR: invalid input syntax for integer: "bad" ![]() I had the same sort of need and found this to work well for me (postgres 8.4): CAST((COALESCE(myfield,'0')) AS INTEGER)
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